Messages

1

General Software Discussion / Re: Java code help

« on: April 17, 2011, 03:39 PM »

---------- Capture Output ----------
> "C:\Program Files\Java\jdk1.6.0_23\bin\java.exe" PassArg4
The values are 25, 50000.0 ,  and T

> Terminated with exit code 0.

see is should have 50000.00  , why doesn't it???

2

General Software Discussion / Re: Java code help

« on: April 17, 2011, 03:19 PM »

ok its working now butr it dsiplays 50000.0   <-- thats odd why wont is show 50000.00   ???

[Select]

// A programs contains the following method:
//public static void display(int arg1, double arg2, char arg3)
//{
// System.out.println("The values are " + arg1 + ", " +
//arg2 + ", and " + arg3);
//}
//Write a statement that calls this method and passes the following varibles as arguements:
//char initial = 'T';
//int age = 25;
//double income = 50000.00


public class PassArg4
{
   public static void main(String[] args)
   {
    
  char initial = 'T';
     int age = 25;
     double income=50000.00;
     display(age, income, initial);

    
     }


// A programs contains the following method:
public static void display(int arg1, double arg2, char arg3)
{
System.out.println("The values are " + arg1 + ", " +
arg2 + " ,  and " + arg3);
}
// Write a statement that calls this method and passes the following varibles as arguments:
// char initial = 'T';
// int age = 25;
// double income = 50000.00
}

Why does it just show 50000.0       <------?
instead of 50000.00    <-- everything else is right

3

General Software Discussion / Java code help

« on: April 17, 2011, 01:34 PM »

I am probably way off

[Select]

// A programs contains the following method:
//public static void display(int arg1, double arg2, char arg3)
//{
// System.out.println("The values are " + arg1 + ", " +
//arg2 + ", and " + arg3);
//}
//Write a statement that calls this method and passes the following varibles as arguements:
//char initial = 'T';
//int age = 25;
//double income = 50000.00

public class PassArg4
{
   public static void main(String[] args)
   {
       
     System.out.println("I am passing values to displayValue.");
           
      System.out.println("Now I am back in main.");
   
  }
       
   public static void display(int arg1, double arg2, char arg3)
   
   {
    int arg1 = 25;
    double arg2 = 50000.00;
    char arg3 = 'T';
 
    display(arg1, arg2, arg3);
    System.out.println("the values are " + arg1 + ", " +
    arg2 + ", and " + arg3);
   
   System.out.println("The values are  " + arg1 + ", " +
    arg2 + ", and " + arg3);
   }
}

4

General Software Discussion / Re: java help

« on: April 03, 2011, 04:34 PM »

it just needs to count the number of times a specified letter occurs in a specified file

5

General Software Discussion / java help

« on: April 03, 2011, 03:33 PM »

Java help open user spec file , count user spec character,

Code: Java [Select]

1. import java.util.Scanner;
2. import java.io.*;
3. public class progChal6
4.  {
5.    public static void main(String[] args) throws IOException
6.    {
7.      
8.      //needed for scanner class
9.       Scanner kb = new Scanner(System.in);
10.       String filename;   // file name
11.       int charCount = 0;
12.      
13.       // get users filename
14.       System.out.print("Enter the file name:  ");
15.       filename = kb.nextLine();
16.       Scanner inputFile = new Scanner(filename);
17.       // get users character
18.       System.out.print("Please enter a character: ");
19.       char userChar = kb.nextLine().charAt(0);
20.       // tell the user what the program does
21.       System.out.println("\n****This program will return how many times" +
22.                           " the character you entered showed up in" +
23.                           " the string you entered.****");
24.                      
25.       while(inputFile.hasNext()) ;
26.       {
27.                (filename.charAt() == userChar);
28.                   {
29.                   charCount++;
30.                   }
31.       }
32.       System.out.println("\nThe specified character " +"\"" + userChar +
33.                           "\" is inside the string " + filename +
34.                           " " + charCount +   " times.\n");            
35.     inputFile.close();
36.     }
37. }