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Developer's Corner / [PHP] Variables in array to int ?
« on: December 09, 2010, 12:19 AM »
I got this IF - FOREACH - THING here (I know that's a bit stupidly done ... adding "," to $num and removing it ...
My excuse is, that Im just a poor student with goal to someday become good at this kind of stuff and currently I don't care if there's something done stupidly ... cause if I ever try to fix that, it will not work):
Now, it somewhy gives me output like this (By var_dumping $num2):
As you can see, every single key is a string.
My guestion is plain simple; how to make those strings int?
I have this example-snippet here, but how do I use it to array? (loop preferred):
-- EDIT --
This seems to turn the variables to int, but it loses the avlue given to them before:
var_dump($num2) outputs now:
My excuse is, that Im just a poor student with goal to someday become good at this kind of stuff and currently I don't care if there's something done stupidly ... cause if I ever try to fix that, it will not work):
Code: PHP [Select]
- ($_GET["num"] as $arvo) $num = $num . $arvo . ",";
- $numchk[] = $num;}
- $numchktostring = $numchk[0];
Now, it somewhy gives me output like this (By var_dumping $num2):
Code: PHP [Select]
- array(7) { [0]=> string(1) "1" [1]=> string(1) "2" [2]=> string(1) "3" [3]=> string(1) "4" [4]=> string(1) "5" [5]=> string(1) "6" [6]=> string(1) "7" }
As you can see, every single key is a string.
My guestion is plain simple; how to make those strings int?
I have this example-snippet here, but how do I use it to array? (loop preferred):
Code: PHP [Select]
- $str = "10";
- $num = (int)$str;
-- EDIT --
This seems to turn the variables to int, but it loses the avlue given to them before:
Code: PHP [Select]
- $i = 0;
- $a = 0;
- While ($i < 7) {
- $num2[$a] = (int)$num2[$a];
- $i++;
- $a++;
- }
var_dump($num2) outputs now:
Code: PHP [Select]
- array(7) { [0]=> int(1) [1]=> int(2) [2]=> int(3) [3]=> int(4) [4]=> int(5) [5]=> int(6) [6]=> int(7) }