[PHP] Variables in array to int ?

[RedPillow]

I got this IF - FOREACH - THING here (I know that's a bit stupidly done ... adding "," to $num and removing it ...
My excuse is, that Im just a poor student with goal to someday become good at this kind of stuff and currently I don't care if there's something done stupidly ... cause if I ever try to fix that, it will not work):

Code: PHP [Select]

1. if (isset($_GET["num"])) { foreach
2. ($_GET["num"] as $arvo) $num = $num . $arvo . ",";
3. $numchk[] = $num;}
4. $numchktostring = $numchk[0];
5. $num2 = explode(",", $numchktostring);
6.  
7. unset($num2[7]);
8. $validchk = count($num2);

Now, it somewhy gives me output like this (By var_dumping $num2):

Code: PHP [Select]

1. array(7) { [0]=>  string(1) "1" [1]=>  string(1) "2" [2]=>  string(1) "3" [3]=>  string(1) "4" [4]=>  string(1) "5" [5]=>  string(1) "6" [6]=>  string(1) "7" }

As you can see, every single key is a string.
My guestion is plain simple; how to make those strings int?

I have this example-snippet here, but how do I use it to array? (loop preferred):

Code: PHP [Select]

1. $str = "10";
2.       $num = (int)$str;

-- EDIT --

This seems to turn the variables to int, but it loses the avlue given to them before:

Code: PHP [Select]

1. $i = 0;
2. $a = 0;
3. While ($i < 7) {
4. $num2[$a] = (int)$num2[$a];
5. $i++;
6. $a++;
7. }

var_dump($num2) outputs now:

Code: PHP [Select]

1. array(7) { [0]=>  int(1) [1]=>  int(2) [2]=>  int(3) [3]=>  int(4) [4]=>  int(5) [5]=>  int(6) [6]=>  int(7) }

[kyrathaba]

Rather than the following...

[Select]

$num = (int)$str;

...you need something like this...

[Select]

$num = intval($str);

The former looks more like casting in C#.